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Let the total work be 120 units. {LCM (24 and 40)}
Combined efficiency of 'C' and 'D' = 120 ÷ 24 = 5 units/day
Efficiency of 'C' = 120 ÷ 40 = 3 units/day
Efficiency of 'D' = 5 - 3 = 2 units/day
So, time taken by 'D' alone = 120 ÷ 2 = 60 days
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