Question
A alone can finish a piece of work in 15 days and B
alone in 20 days. They work together for 4 days and then A leaves. In how many more days will B finish the remaining work alone?Solution
Take total work = LCM(15, 20) = 60 units. Aβs rate = 60/15 = 4 units/day Bβs rate = 60/20 = 3 units/day Together for 4 days: Work done = (4 + 3) Γ 4 = 7 Γ 4 = 28 units Remaining work = 60 β 28 = 32 units Now only B works: Time = remaining work / Bβs rate = 32 / 3 = 10β days Answer: B will take 10β days more.
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