Question
A alone can finish a piece of work in 15 days and B alone in 20 days. They work together for 4 days and then A leaves. In how many more days will B finish the remaining work alone?
Solution
Take total work = LCM(15, 20) = 60 units. A’s rate = 60/15 = 4 units/day B’s rate = 60/20 = 3 units/day Together for 4 days: Work done = (4 + 3) × 4 = 7 × 4 = 28 units Remaining work = 60 − 28 = 32 units Now only B works: Time = remaining work / B’s rate = 32 / 3 = 10⅔ days Answer: B will take 10⅔ days more.
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