Question
βPβ and βQβ can complete a task together in 24
days. If βPβ alone can do it in 40 days, find the number of days βQβ alone will take to finish the task.Solution
ATQ, Let the total work be LCM(24, 40) = 120 units. Combined efficiency of βPβ and βQβ = 120 Γ· 24 = 5 units/day Efficiency of βPβ = 120 Γ· 40 = 3 units/day Efficiency of βQβ = 5 - 3 = 2 units/day Time taken by βQβ alone = 120 Γ· 2 = 60 days
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