Question
P can do a piece of work in 20 days, Q can do the same
piece of work in 24 days while R can do it in 30 days. They started working together but after 4 days ‘P’ left the work and the remaining work was completed by Q and R together. Find in how many days will the work be completed?Solution
P – 20 days P – 6 unit Q – 24 days LCM = 120 Q – 5 unit R – 30 days R – 4 unit Work of all 3 per day is (6 + 5 + 4) – 15 units All worked for 4 days. So, 4 days work is 4 × 15 = 60 units Remaining work = 120 – 60 = 60 units That work done by Q and R their per day unit = (5 + 4) = 9 unit Remaining work done by Q and R is `60/9` days = `6 2/3` days
Statements: R ≥ S > T; U < V ≤ T; V > W
Conclusions:
I. R > V
II. W < S
III. T > W
Statements: A @ D % M % N; M $ P $ Q
Conclusions : I. D % Q I...
Statements: Q ≤ R < A; R ≥ N > S; S ≥ T > U
Conclusions:
I. A > N
II. U < N
III. S ≥ Q
Answer the questions based on the information given below.
A @ B means A is not smaller than B
A & B means A is neither smaller than nor...
Which of the following should be placed in the blank spaces respectively ( in the same order from left to right) in order to complete the given express...
Which of the following symbols respectively should replace the question marks in order to make the expression V ≥ M and X ≤ H definitely true?
<...If “M % N # O © P @ S © T $ W” is true then which of the following is definitely not true?
(i) M # P
(ii) O © T
(iii) N #...
Statement: L ≥ M ≤ R = S; M > N ≥ P
Conclusions: I. P ≤ M II. L > N
Statements:
A < B = C; D = E ≤ F ≤ G; E ≤ B
Conclusions:
I). G ≥ C
II). D ≤ B
III). C ≥ D
Statement: T>U<V<X=C>S ;U<P ≥X
I. T < P
II. P > S
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