Question
P can do a piece of work in 20 days, Q can do the same
piece of work in 24 days while R can do it in 30 days. They started working together but after 4 days ‘P’ left the work and the remaining work was completed by Q and R together. Find in how many days will the work be completed?Solution
P – 20 days P – 6 unit Q – 24 days LCM = 120 Q – 5 unit R – 30 days R – 4 unit Work of all 3 per day is (6 + 5 + 4) – 15 units All worked for 4 days. So, 4 days work is 4 × 15 = 60 units Remaining work = 120 – 60 = 60 units That work done by Q and R their per day unit = (5 + 4) = 9 unit Remaining work done by Q and R is `60/9` days = `6 2/3` days
Statements : R < O ≤ P < Q; M < L ≤ N > O; S < Q ≤ K
Conclusions:
I. M < K
II. N > R
III. O < S
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Conclusions: I. K @ U II. K % U III. E @ U
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Statement: A ≤ B ≤ C > D; E < D; F > E
Conclusions: I. D > A II. E < C
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Statements: X < H = U ≤ I < N = M, M > B ≥ V
Conclusions:
I. I > V
II. U ≥ M
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