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    Question

    β€˜A’ is 80% more efficient than β€˜B’. β€˜A’ and

    β€˜B’ work together for 5 days after which β€˜A’ is replaced by β€˜C’. β€˜B’ and β€˜C’ together take 10 more days to finish the work. If β€˜A’ alone could’ve finished the whole work in 20 days, then find the time taken by β€˜C’ to finish 60% work alone.
    A 14 days Correct Answer Incorrect Answer
    B 12 days Correct Answer Incorrect Answer
    C 15 days Correct Answer Incorrect Answer
    D 18 days Correct Answer Incorrect Answer
    E 24 days Correct Answer Incorrect Answer

    Solution

    Let the efficiency of 'B' be 'x' units/day So, efficiency of 'A' = x Γ— 1.8 = '1.8x' units/day Total work = 20 Γ— 1.8x = '36x' units So, work done by 'A' and 'B' together in 5 days = (x + 1.8x) Γ— 5 = '14x' units So, remaining work = 36x - 14x = '22x' units So, efficiency of 'B' and 'C' together = 22x Γ· 10 = '2.2x' units per day So, efficiency of 'C' = 2.2x - x = '1.2x' units/day So, required time = (36x Γ— 0.6) Γ· 1.2x = 18 days

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