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      Question

      ‘A’ and ‘B’, alone can complete a work in 25

      days and 50 days, respectively. Both of them started the work together but ‘A’ left the work when 2% of the work was remaining which is then completed by ‘B’ alone, then find the total time required to complete the whole work in this way.
      A 17(1/3) Correct Answer Incorrect Answer
      B 16(1/3) Correct Answer Incorrect Answer
      C 15(1/3) Correct Answer Incorrect Answer
      D 19(1/3) Correct Answer Incorrect Answer
      E None of these Correct Answer Incorrect Answer

      Solution

      Let the total work be 250 units {L.C.M of 25 and 50 units} Efficiency of ‘A’ = (250/25) = 10 units/day Efficiency of ‘B’ = (250/50) = 5 units/day Remaining work = 0.02 × 250 = 5 units Number of days taken by ‘A’ and ‘B’ to complete 245 units = 245/(10 + 5) =   days Number of days taken by ‘B’ to complete 5 units of the work = (5/5) = 1 day Total time taken to complete the work =       + 1 =      day

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