Question
‘A’ and ‘B’, alone can complete a work in 25
days and 50 days, respectively. Both of them started the work together but ‘A’ left the work when 2% of the work was remaining which is then completed by ‘B’ alone, then find the total time required to complete the whole work in this way.Solution
Let the total work be 250 units {L.C.M of 25 and 50 units} Efficiency of ‘A’ = (250/25) = 10 units/day Efficiency of ‘B’ = (250/50) = 5 units/day Remaining work = 0.02 × 250 = 5 units Number of days taken by ‘A’ and ‘B’ to complete 245 units = 245/(10 + 5) = 
days Number of days taken by ‘B’ to complete 5 units of the work = (5/5) = 1 day Total time taken to complete the work = 
+ 1 = 
day
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