Question
There is enough food in a camp to last for 60 days if each of the 20 soldiers present at the camp eat 5 times a day. After 30 days, 10 more soldiers joined the camp and remaining ate only twice a day. For how many days (from start) will the food last?
Solution
Let the eating capacity of each soldier be 'x' units So, total food at the camp = (60 X 20 X 5 X x) = '6000x' units And food remaining after 30 days = 6000x - (30 X 20 X 5 X x) = '3000x' units So, required time = 3000x ÷ (x X 2 X 30) = 50 days So, the food will last for a total of 50 + 30 = 80 days
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