Question
‘C’ and ‘D’ can together complete a piece of
work in 20 days. If ‘C’ alone can do it in 50 days, find the number of days ‘D’ will take to complete it alone.Solution
ATQ, Let total work = LCM(20, 50) = 100 units. Combined efficiency of ‘C’ and ‘D’ = 100 ÷ 20 = 5 units/day Efficiency of ‘C’ = 100 ÷ 50 = 2 units/day Efficiency of ‘D’ = 5 - 2 = 3 units/day Time taken by ‘D’ alone = 100 ÷ 3 = (100/3) days
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