Question
βCβ and βDβ can together complete a piece of
work in 20 days. If βCβ alone can do it in 50 days, find the number of days βDβ will take to complete it alone.Solution
ATQ, Let total work = LCM(20, 50) = 100 units. Combined efficiency of βCβ and βDβ = 100 Γ· 20 = 5 units/day Efficiency of βCβ = 100 Γ· 50 = 2 units/day Efficiency of βDβ = 5 - 2 = 3 units/day Time taken by βDβ alone = 100 Γ· 3 = (100/3) days
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