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• Oxidation state of oxygen is usually -2, but in compounds with fluorine, it can be different. • In OF₂ (oxygen difluoride), fluorine is more electronegative and has an oxidation state of -1. • Let x be the oxidation state of oxygen: x+2(−1)=0x + 2(-1) = 0 x+2(−1)=0x−2=0x - 2 = 0 x−2=0x=+2x = +2 x=+2 • Hence, the oxidation state of oxygen in OF₂ is +2.
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