Question
Which one of the following is the oxidation state of
oxygen in OF₂?Solution
• Oxidation state of oxygen is usually -2, but in compounds with fluorine, it can be different. • In OF₂ (oxygen difluoride), fluorine is more electronegative and has an oxidation state of -1. • Let x be the oxidation state of oxygen: x+2(−1)=0x + 2(-1) = 0 x+2(−1)=0x−2=0x - 2 = 0 x−2=0x=+2x = +2 x=+2 • Hence, the oxidation state of oxygen in OF₂ is +2.
12 10 13 18.5 25.50 ...
7, 14, 42, 210, 1470, ?
6, 17, 21, 47, ?, 107
21 84 168 172 ? 348
...315 146 267 ? 235 210
14 20 35 ? 433 2167
...18, 32, 50, 82, 132, ?
840 400 180 ? 15 -12.5
...22 23 32 57 106 ?
Three series are given below. You have to find the values of P, Q and R, then establish a relationship among them.
I: 210, P , 233, 64,...
