Question
A can complete a piece of work in 10 days and B can complete it in 15 days. They start working together, but B leaves after 3 days. In how many more days will A finish the remaining work?
Solution
Assume total work = LCM(10, 15) = 30 units. A’s rate = 30/10 = 3 units/day B’s rate = 30/15 = 2 units/day Work done in first 3 days by A and B: Daily work together = 3 + 2 = 5 units Work in 3 days = 5 × 3 = 15 units Remaining work = 30 − 15 = 15 units Now only A works: Time taken = 15 / 3 = 5 days Answer: A will take 5 more days.
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