Question
There is enough food in a camp to last for 60 days if each of the 30 soldiers present at the camp eat 4 times a day. After 40 days, 10 soldiers left the camp and remaining ate only 3 times a day. For how many days (from start) will the food last?
Solution
Let the eating capacity of each soldier be 'x' units So, total food at the camp = (60 X 30 X 4 X x) = '7200x' units And food remaining after 40 days = 7200x - (40 X 30 X 4 X x) = '2400x' units So, required time = 2400x ÷ (x X 3 X 20) = 40 days So, the food will last for a total of 40 + 40 = 80 days
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