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      Question

      'P' alone can do a job in 15 days. 'Q' is 60% more

      efficient than 'P'. 'P' and 'Q' started the work together, but 'P' left after 5 days. Find the time taken by 'Q' to complete the remaining work.
      A 10 days Correct Answer Incorrect Answer
      B 3.25 days Correct Answer Incorrect Answer
      C 1.25 days Correct Answer Incorrect Answer
      D 5 days Correct Answer Incorrect Answer

      Solution

      ATQ,

      Let the efficiency of 'P' be '5x' units/day

      So, efficiency of 'Q' = 5x × (1.6) = 8x units/day

      So, total work = 5x × 15 = 75x units

      Work done by 'P' and 'Q' together in 5 days = (5x + 8x) × 5 = 65x units

      So, time taken by 'Q' to finish the remaining work = (75x - 65x) ÷ 8x = 1.25 days

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