Question
Ramesh needs half the time that
Suresh needs to complete a job. Suresh and Tarun together complete it in 27 days, whereas Ramesh and Tarun take 18 days. How many days will Ramesh and Suresh require together?Solution
ATQ, Let the total work be 54 units. {LCM (27 and 18)} Efficiency of Suresh + Tarun = 54 ÷ 27 = 2 units/day Efficiency of Ramesh + Tarun = 54 ÷ 18 = 3 units/day Let: Suresh = s, Tarun = t Ramesh = 2s So, (s + t) = 2 ……… (i) (2s + t) = 3 ……… (ii) Subtracting (i) from (ii): s = 1 Efficiency of Ramesh = 2 × 1 = 2 units/day Required time = 54 ÷ (1 + 2) = 18 days
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