Question
A and B together can complete a work in 10 days. B and C
together can do it in 12 days, and A and C together can do it in 15 days. In how many days will all three working together finish the work?Solution
Let total work = 1 unit. Rates: A + B = 1/10 work per day B + C = 1/12 A + C = 1/15 Add all three equations: (A + B) + (B + C) + (A + C) = 2(A + B + C) = 1/10 + 1/12 + 1/15 Find RHS: LCM of 10, 12, 15 = 60 1/10 = 6/60, 1/12 = 5/60, 1/15 = 4/60 Sum = (6 + 5 + 4)/60 = 15/60 = 1/4 So 2(A + B + C) = 1/4 ⇒ A + B + C = 1/8 work per day Time to finish 1 work together = 1 ÷ (1/8) = 8 days.
72 – 4(40 + 24 ÷ 6 × 6 – 4 × 4) + 40
62.94% of 1800 - 15.03 % of 2400 = ?
- What will come in place of (?), in the given expression.
(12% of 250) + (30% of 400) = ? √324 + √576 = ?/ √9
6 × 1.8 × 0.25 × 70 = ? + 9.5
What will come in the place of question mark (?) in the given expression?
65% of 900 - 45% of 600 = ? X 3
70 % of 640 + 75 % of 360 - 19 × 12 = ?
√(2670+ √(1141+ √(260- √(1251- √(637+ √1521) ) ) ) ) =?
{17 + √2601}/(? + 2) = 17
