Question
'A' can do 50% of work in 10 days, whereas 'B' can do
25% of the same work in 8 days. 'A' and 'B' started the work, but 'B' left the work 'n' days before completion of work. If the whole work is completed in 15 days, then find the value of [0.8n + (n²/10) ].Solution
ATQ, Time taken by 'A' to complete the entire work = (10/50)×100 = 20 days Time taken by 'B' to complete the entire work = (8/25 )×100 = 32 days Let the total work be 160 units (LCM of 20 and 32). Efficiency of 'A' = 160/20 = 8 units/day Efficiency of 'B' =160/32 = 5 units/day ATQ, (8×15)+{5×(15−n)} = 160 120+(75−5n) = 160 195−5n = 160 5n = 35 n = 7 Therefore, required value = 
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