Question
A and B together can finish a work in 10 days. If A
alone can finish it in 25 days, in how many days can B alone finish it?Solution
Let total work = 1 unit. (A + B)’s 1-day work = 1/10 A’s 1-day work = 1/25 So B’s 1-day work = 1/10 − 1/25 LCM(10,25) = 50 1/10 = 5/50 1/25 = 2/50 B’s 1-day work = (5 − 2)/50 = 3/50 Time for B alone = 1 ÷ (3/50) = 50/3 days
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