Question
‘R’ completes a job in 10 days. ‘S’ is twice as
efficient as ‘R’. How much time will they take to complete 120% of the work together?Solution
Let total work = 100x units.
Efficiency of R = 100x / 10 = 10x units/day.
S is twice as efficient, so S's efficiency = 2 × 10x = 20x units/day.
120% of work = 100x × 1.20 = 120x units.
Combined efficiency = 10x + 20x = 30x units/day.
Time taken = 120x / 30x = 4 days.
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