Question
‘R’ completes a job in 10 days. ‘S’ is twice as
efficient as ‘R’. How much time will they take to complete 120% of the work together?Solution
Let total work = 100x units.
Efficiency of R = 100x / 10 = 10x units/day.
S is twice as efficient, so S's efficiency = 2 × 10x = 20x units/day.
120% of work = 100x × 1.20 = 120x units.
Combined efficiency = 10x + 20x = 30x units/day.
Time taken = 120x / 30x = 4 days.
I. 8x² + 2x – 3 = 0
II. 6y² + 11y + 4 = 0
Quantity I: The price of rice is decreased by 30%, by how much % the consumption is increase so that the expenditure will decreased by 10%?
Quant...
I. 4 x ² - 4 x + 1 = 0
II. 4 y ² + 4 y + 1 = 0
...I. 27(p + 2) = 2p(24 – p)
II. 2q2 – 25q + 78 = 0
I. 35x² + 83x + 36 = 0
II. 42y² + 53y + 15 = 0
What are the coordinates of the point which divides the line joining (-1, 7) and (4, 3) in the ratio 2:3?
I. 49y2 + 35y + 6 = 0
II. 12x2 + 17 x + 6 = 0
Solve the quadratic equations and determine the relation between x and y:
Equation 1: x² - 42x + 392 = 0
Equation 2: y² - 46y + 480 = 0
I. 4x2 + 25x + 36 =0
II. 2y2 + 5y + 3 = 0
I. (x13/5 ÷7) = 5488 ÷ x7/5
II. (y2/3 × y2/3 ) ÷ √4 = (343y)1/3...
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