Question
A is twice as efficient as B. Together they can complete
a work in 18 days. In how many days can A alone complete the work?Solution
ATQ, Let B’s 1-day work = x Then A’s 1-day work = 2x Together: 3x = 1/18 x = 1/54 So A’s rate = 2x = 2/54 = 1/27 Hence A alone takes 27 days.
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