Question
Ravi and Ramesh can do a job together in 20 days. They
worked together for 12 days and then Suresh finished the remaining work alone in 10 days.Find how long Suresh alone will take to complete 90% of the total job.Solution
ATQ,
Fraction of work done by Ravi and Ramesh = 12 / 20 = 3/5
Fraction of work done by Suresh = 1 - 3/5 = 2/5
So, number of days taken by Suresh alone to complete the entire work = 10 ÷ (2/5) = 25 days
So, time taken by Suresh to complete 90% of the work = 25 × 0.90 = 22.5 days
72 x 60 x 22 x 32 =?
If a³ - b³ = (a - b)(a² + ab + b²), find a³ - b³ when a = 10 and b = 4.
(√2704 x 55)/(245 + 120) =?
168Â Â Â Â Â 163Â Â Â Â Â Â 153Â Â Â Â Â Â 138Â Â Â Â Â 118Â Â Â Â Â ?
...? = 20% of 1200 + 256
√ 225 x 24 - √ 144 x 18 = ?
30% of 215 + 135% of ? = 469.5
[∛(3375/19683  )- ∛(125/1728  )  ] ÷ ∛(64/729)  = ? - 3/8Â
10 * 15 + 30% of 150 + 80% of 200 = ?
The value of 15 × 14 – 30 + (32 + 17) is: