Question
Working alone, B can complete the work in 30 days. C is
twice as efficient as B and A takes 3 days more than it takes C to complete the work. Working together, in how much time would they be able to complete 7 such works?Solution
Time taken by B to complete the work = 30 days Time taken by C to complete the work = 30/2 = 15 days Time taken by A to complete the work alone = 15 + 3 = 18 days Work done by A, B and C together in 1 day. ⇒ (1/30 + 1/15 + 1/18) = (3 + 6 + 5)/90 = 14/90 this means if would take 45/7 days for A, B and C to complete the work together ∴ Time taken A, B and C to complete 7 works = 7 × 45/7 days = 45 days
Statement: L ≥ M ≤ R = S; M > N ≥ P
Conclusions:
I. P ≤ M
II. L > N
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Statements: D > E > G ≤ H < I; G > P > F
Conclusions:
I. D > F
II. P < I
III. D > I
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Statements : T ≥ W > X; Q = J < X; Q < O ≥ D
Conclusions :
I. J < W
II. O > W
III. D > J
...In the question, assuming the given statements to be true, find which of the conclusion (s) among given three conclusions is/are definitely true and th...
Statement: M < N ≤ O = P, Q ≥ O ≤ R ≤ Z
Conclusion: I. Q > MÂ Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â II. Z > M
...
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