Question
Working alone, B can complete the work in 30 days. C is
twice as efficient as B and A takes 20 days more than it takes C to complete the work. Working together, in how much time would they be able to complete 9 such works?Solution
Time taken by B to complete the work = 30 days
Time taken by C to complete the work = 30/2 = 15 days
Time taken by A to complete the work alone = 20 + 15 = 35 days
Work done by A, B and C together in 1 day.
⇒ (1/30 + 1/15 + 1/35) = (7 + 14 + 6)/210 = 27/210
this means if would take 210/27 days for A, B and C to complete the work together
∴ Time taken A, B and C to complete 9 works = 9 × 210/27 days = 70 days
More Time and work Questions
{(80% of 650 + 25 × 12) – 20 × ?} = 760
- What will come in place of (?), in the given expression.
125% of 96 + 33% of 300 = ? 20% of 550 × 25% of 80 = ?2 × 22
(96% of 1100) + 92 × 4 = ? + 46 × 16
- Find the simplified value of the given expression.
1024 ÷ 16 + 800 ÷ √64 + ? = 200 * 2
5.45% of 1854 – 37.5% of 1096 = ? – 48% of 630
√ (12+√ (12+√ (12+ ⋯ ∞ ))
74% of 2840 + 80% of 1640 - ?= 47²
4.56 + 56.4 + 64.5 = ? + 10.46
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