Question
βAβ alone can do some work in 10 days. βBβ and
βCβ together can do the same work in 4 days. If βBβ is half as efficient as βAβ, then find the time taken by βCβ to complete the work alone.Solution
Let the total work be 20 units. {LCM (10 and 4)} So, efficiency of βAβ = (20/10) = 2 units/day So, efficiency of βBβ = (2 x 0.5) = 1 unit/day Efficiency of βBβ and βCβ together = (20/4) = 5 units/day So, efficiency of βCβ = 5 β 1 = 4 units/day So, time taken by βCβ to finish the work alone = (20/4) = 5 days
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