Question
Average speed of ‘A’ during a 22-hour journey is 22
km/h. If he covered the first 280 km of his journey at a speed of 20 km/h, then find the speed at which ‘A’ travelled during the remaining journey.Solution
Total distance covered by ‘A’ = 22 × 22 = 484 km Time taken to cover 280 km = 280/20 = 14 hours Time taken to cover remaining distance = 22 – 14 = 8 hours So, required speed = {(484 – 280)/8} = 25.5 km/h
More Time and work Questions
√3598 × √(230 ) ÷ √102= ?
15% of 2400 + (√ 484 – √ 256) = ?
(13)2 - 3127 ÷ 59 = ? x 4
6269 + 0.25 × 444 + 0.8 × 200 = ? × 15
...(53 + 480 ÷ 4)% of 20 = ?% of 70
Find the simplified value of the following expression:
62 + 122 × 5 - {272 + 162 - 422}
(15 × 225) ÷ (45 × 5) + 480 = ? + 25% of 1240
√ [? x 11 + (√ 1296)] = 16
11 × 25 + 12 × 15 + 14 × 20 + 15 = ?
