Question
Three workers, A, B, and C, can complete a task in 40
days, 72 days, and 45 days respectively. They start working together, but A leaves 20 days before the work is completed, and C continues working for 5 more days after A leaves. How many days does it take to complete the whole work?Solution
Let, total amount of work = 360 units (LCM of 40, 72 and 45) Efficiency of βAβ = 360/40 = 9 units/day Efficiency of βBβ = 360/72 = 5 units/day Efficiency of βCβ = 360/45 = 8 units/day Let, the whole work is completed in βxβ days So, βAβ worked for βx β 20β days And, βCβ worked for x β 20 + 5 = βx β 15β days So, 9(x β 20) + 8(x β 15) + 5 Γ x = 360 Or, 22x = 660 Or, x = 30
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