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ATQ,
Let the efficiency of 'Lokesh' and 'Meena' be 'x' units/day and 'y' units/day respectively.
Given, 0.4 × work done by 'Lokesh' = 0.3 × work done by 'Meena'
So, 0.4 × x = 0.3 × y
So, y = (4/3) x
So, total work = 28 × × = 28x units
Or, required total efficiency = x + y = x + (4/3) x = (7x/3) units/day
So, number of days = {28x ÷ (7x/3)} = 12 days
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