Question
It is given that 40% of the work completed by Lokesh is
equal to 30% of the work completed by Meena. If Lokesh alone can complete the entire work in 28 days, determine the number of days required for Lokesh and Meena to complete the work when working together.Solution
ATQ,
Let the efficiency of 'Lokesh' and 'Meena' be 'x' units/day and 'y' units/day respectively.
Given, 0.4 × work done by 'Lokesh' = 0.3 × work done by 'Meena'
So, 0.4 × x = 0.3 × y
So, y = (4/3) x
So, total work = 28 × × = 28x units
Or, required total efficiency = x + y = x + (4/3) x = (7x/3) units/day
So, number of days = {28x ÷ (7x/3)} = 12 days
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