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    Question

    It is given that 40% of the work completed by Lokesh is

    equal to 30% of the work completed by Meena. If Lokesh alone can complete the entire work in 28 days, determine the number of days required for Lokesh and Meena to complete the work when working together.
    A 12 days Correct Answer Incorrect Answer
    B 24 days Correct Answer Incorrect Answer
    C 20 days Correct Answer Incorrect Answer
    D 32 days Correct Answer Incorrect Answer
    E None of these Correct Answer Incorrect Answer

    Solution

    ATQ,

    Let the efficiency of 'Lokesh' and 'Meena' be 'x' units/day and 'y' units/day respectively.

    Given, 0.4 Ă— work done by 'Lokesh' = 0.3 Ă— work done by 'Meena'

    So, 0.4 Ă— x = 0.3 Ă— y

    So, y = (4/3) x

    So, total work = 28 Ă— Ă— = 28x units

    Or, required total efficiency = x + y = x + (4/3) x = (7x/3) units/day

    So, number of days = {28x Ă· (7x/3)} = 12 days

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