Question
‘D’ alone can complete a task in 20 days. ‘E’ is
40% less efficient than ‘D’. They worked together for 5 days, after which ‘D’ stopped working. What percentage of the total work was completed by ‘E’?Solution
ATQ,
Let the efficiency of ‘D’ be ‘5x’ units/day
So, efficiency of ‘E’ = 5x × (3/5) = ‘3x’ units/day
Total work = 20 × 5x = ‘100x’ units
Work done by ‘D’ in 5 days = 5x × 5 = ‘25x’ units
Work done by ‘E’ in 5 days = 3x × 5 = ‘15x’ units
Total work done in 5 days = 40x
Remaining work = 100x – 40x = ‘60x’ units
Work done by ‘E’ alone = 60x units
Total work by ‘E’ = 15x + 60x = 75x
Required percentage = {(75x/100x) × 100} = 75%
Equation 1: x² - 200x + 9600 = 0
Equation 2: y² - 190y + 9025 = 0
I: x2 + 31x + 228 = 0
II: y2 + 3y – 108 = 0
I). 5p2 - p - 4 = 0
II). q2 - 12q + 27 = 0
I). p2 - 26p + 165 = 0
II). q2 + 8q - 153 = 0
l). 3p + 2q = 27
ll). 4p - 3q = 2
I. 2b2 + 31b + 99 = 0
II. 4a2 + 8a - 45 = 0
I. 6x² + 77x + 121 = 0
II. y² + 9y - 22 = 0
I. 2p2 - 3p – 2 = 0 II. 2q2 - 11q + 15 = 0
I: √(100 x4 + 125x4) + 7x + 41/2 = -4x
II: 3√(64y3) x 2y + 19y + 72 = -3y +...
If the roots of the quadratic equation 6m² + 7m + 8 = 0 are α and β, then what is the value of [(1/α) + (1/β)]?
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