Question
"'Mahesh' is 40% less efficient than 'Neeraj.' 'Neeraj'
takes 30 days fewer than 'Mahesh' to finish the same work. Find the time taken by 'Neeraj' to finish the work while working at 80% of his efficiency."Solution
ATQ, Let the efficiency of 'Neeraj' be '10n' units/day So, efficiency of 'Mahesh' = 10n × 0.6 = '6n' units/day So, ratio of efficiency of time taken by 'Mahesh' and 'Neeraj' = 10n:6n = 5:3 Let time taken by 'Mahesh' and 'Neeraj' to finish some work be '5m' day and '3m' days. So, 5m - 3m = 30 So, 2m = 30 So, m = 15 And time taken by Neeraj to finish the work = 3 × 15 = 45 days So, required time = 45 ÷ 0.8 = 56.25 days
51, 60, 78, ?, 141, 186
3, 8, 18, 33, 53, ?
- 6, ?, 9816, 9825, 19429, 19438
84, 63, ?, 283.5, 1701
14, 20, 29, 44, 65, ?
3.6 × 1.5 + 8.4 × 2.5 – 9.2 × 3.5 = ? – 9.2 × 4.4
18Â Â Â 19Â Â Â 34Â Â Â 111Â Â Â Â 428Â Â Â Â 2165Â Â Â Â ?
...7, 8, 18, 57, 232, ?
What will come in place of the question mark (?) in the following series?
102, 111, 136, 185, 266, ?
10, 10, 15, 30, 75, ?
