Question
"'Mahesh' is 40% less efficient than 'Neeraj.' 'Neeraj'
takes 30 days fewer than 'Mahesh' to finish the same work. Find the time taken by 'Neeraj' to finish the work while working at 80% of his efficiency."Solution
ATQ, Let the efficiency of 'Neeraj' be '10n' units/day So, efficiency of 'Mahesh' = 10n × 0.6 = '6n' units/day So, ratio of efficiency of time taken by 'Mahesh' and 'Neeraj' = 10n:6n = 5:3 Let time taken by 'Mahesh' and 'Neeraj' to finish some work be '5m' day and '3m' days. So, 5m - 3m = 30 So, 2m = 30 So, m = 15 And time taken by Neeraj to finish the work = 3 × 15 = 45 days So, required time = 45 ÷ 0.8 = 56.25 days
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