Question
Akhil and Nikhil together can complete a work in 15 days
while Nikhil alone takes 20 days to complete 50% of the work. If the efficiency of Sachin is 20% more than that of Akhil, then find the time taken by Sachin alone to complete the whole work.Solution
Time taken by Nikhil to complete the whole work alone = 20/0.50 = 40 days Let the total work = 120 units Efficiency of (Akhil + Nikhil) = 120/15 = 8 units/day Efficiency of Nikhil = 120/40 = 3 units/day Efficiency of Akhil = 8 - 3 = 5 units/day Therefore efficiency of Sachin = 1.20 x 5 = 6 units/day Time taken by Sachin to complete the whole work alone = 120/6 = 20 days
`(sqrt(960.87)xx9.932+sqrt(629.998)xx26.385)/(sqrt(1028.902)xx4.977)=?`
What approximate value will come in place of the question mark (?) in the following question? (Note: You are not expected to calculate the exact value.)...
- What approximate value will come in place of the question mark (?) in the following question? (Note: You are not expected to calculate the exact value.)
99.99% of 9.99 + 299.98% of 129.98 = ?2Â
- What approximate value will come in place of the question mark (?) in the following question? (Note: You are not expected to calculate the exactvalue.)
(29.98% of 9840) + ? + (19.899% of 8490) = 7560
- What approximate value will come in place of the question mark (?) in the following question? (Note: You are not expected to calculate the exact value.)
What approximate value will come in place of the question mark (?) in the following question? (Note: You are not expected to calculate the exact value.)...
4650.12 ÷ √8648.88 + √27.08 * √1727.85 = ? – 609.10 ÷ 87.07                     Â
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