Question
Akhil and Nikhil together can complete a work in 5 days
while Nikhil alone takes 10 days to complete 40% of the work. If the efficiency of Sachin is 25% more than that of Akhil, then find the time taken by Sachin alone to complete the whole work.Solution
Time taken by Nikhil to complete the whole work alone = 10/0.40 = 25 days Let the total work = 25 units Efficiency of (Akhil + Nikhil) = 25/5 = 5 units/day Efficiency of Nikhil = 25/25 = 1 units/day Efficiency of Akhil = 5 - 1 = 4 units/day Therefore efficiency of Sachin = 1.25 x 4 = 5 units/day Time taken by Sachin to complete the whole work alone = 25/5 = 5 days
230 192 172 ? 122 100
...What value should come in the place of (?) in the following number series?
64, 80, 104, ?, 176, 224
97, 106, ?, 195, 411, 460
What will come in place of the question mark (?) in the following series?
29, 42, ?, 95, 135, 184
Find the missing term:
2, 6, 15, 31, 56, ?
32   48   96   ?   720   2520
82, 98, 130, 178, 242, ?
4 10 ? 62.5 156.25 390.625
...140, 146, 170, 224, ?, 470
7 47 ? 223 359 527
...
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