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Let the total work = 360 units Then, efficiency of ‘A’ = (360/40) = 9 units/hour Work completed by ‘A’ alone in 20 hours = 9 × 20 = 180 units Remaining work = 360 – 180 = 180 units So, efficiency of ‘B’ = 180/20 = 9 units/hour Therefore, combined efficiency of ‘A’ and ‘B’ = 9 + 9 = 18 units/hour So, time taken by ‘A’ and ‘B’ together to complete the work = (360/18) = 20 hours
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