Question
Two pipes, A and B, can fill a tank together in 72 minutes. Both pipes are turned on at the same time. However, pipe B is turned off after 60 minutes, and the tank gets completely filled in a total of 1 hour and 20 minutes. How long would it take for pipe B alone to fill the tank?
Solution
Let pipe A and B can fill ‘x’ units and ‘y’ units, of water per minute.
Total capacity of tank = 72 × (x + y) units
According to question;
60 × (x + y) + 20x = 72 × (x + y)
80x + 60y = 72x + 72y
8x = 12y
2x = 3y
x = 1.5y
Desired time = 72 × (1.5y + y)/y = 180 minutes = 3 hours
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