Question
36 women can complete a task in 20 days. If 18 women
start the task and after 15 days ‘y’ more women join, ensuring the remaining work is completed in another 15 days, find the value of ‘y’. (All women have the same efficiency)Solution
Total work = 36 women × 20 days = 720 units Work completed by 18 women in 15 days = 18 women × 15 days = 270 units  Remaining work to be completed by (18 + y) women = 720 – 270 = 450 units Therefore, (18 + y) × 15 = 450 Or, 18 + y = 450 / 15 Or, 18 + y = 30 Or, y = 30 – 18 = 12 Number of women added = 12
If p = 24 - q - r and pq + r(q + p) = 132, then find the value of (p² + q² + r²).
((99.9 - 20.9)² + (99.9 + 20.9)² )/(99.9 x 99.9 + 20.9 x 20.9) = ?
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Find the value of the given expression-
(4x+4 -5× 4x+2) / 15×4x – 22×4x
If 4x² + y² = 40 and x y = 6, then find the value
of 2x + y?
If p = 40 - q - r and pq + r(q + p) = 432, then find the value of (p² + q² + r²).
47.98 × 4.16 + √325 × 12.91 + ? = 79.93 × 5.91
If x + y = 4 and (1/x) + (1/y) = 24/7, then the value of (x3 + y3).
- If p = 20 - q - r and pq + r(p + q) = 154, then find the value of (p² + q² + r²).
If a = (√2 - 1)1/3, then the value of (a-1/a)3 +3(a-1/a) is:
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