Question
Rohit is five times as efficient as Sohan and twice as
efficient as Mohan. If Sohan takes 15 days to finish some work, then find the time taken by Rohit and Mohan to do the same work together.Solution
Since, Rohit is five times as efficient as Sohan, he will take one-fifth the time taken by Sohan to finish the work. So, time taken by Rohit to do the work = 15 ÷ 5 = 3 days And, Rohit is twice as efficient as Mohan, so Mohan will take double the time taken by Rohit. So, time taken by Mohan to do the work = 2 × 3 = 6 days Let the total work be '6x' units. So, efficiency of Rohit = 6x ÷ 3 = '2x' units/day And, efficiency of Mohan = 6x ÷ 6 = 'x' units/day So, required time = 6x ÷ (2x + x) = 2 days Hence, option a.
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