Question
Bittu can finish a task by
himself in 60 days, while Anoop and Bittu working together can complete the same task in 28 days. If Anoop starts the task alone and works for 35 days before stopping, how many additional days would Bittu need to complete the remaining work on his own?Solution
ATQ,
Let the total task = L.C.M of 60 and 28 = 420 units Then, efficiency of ‘Bittu’ alone = 420 ÷ 60 = 7 units/day Combined efficiency of ‘Anoop’ and ‘Bittu’ = 420 ÷ 28 = 15 units/day So, efficiency of ‘Anoop’ alone = 15 – 7 = 8 units/day task done by ‘Anoop’ alone in 35 days = 8 × 35 = 280 units Remaining task = 420 – 280 = 140 units So, time taken by ‘Bittu’ alone to complete the remaining task = 140 ÷ 7 = 20 days.
?% of (168 ÷ 8 × 20) = 126
20% of 1500 – 75% of 200 = 125% of ?
Find the value of 16 X [(8 - 5) of 12 ÷ 4].
√196 + (0.25 × 144) + 19 = ? + 72
22 * 6 + 45% of 90 + 65% of 180 = ?
52% of 400 + √(?) = 60% of 600 - 25% of 400
(25 × 12 + 30 × 8 – 22 × 10) = ?
What will come in the place of question mark (?) in the given expression?
(240% of 175 ÷ √16) X 6 + 80% of 400 = ?3 + 179 + 42
What will come in the place of question mark (?) in the given expression?
(144 × 16 ÷ 12) × 6 = ?
808 ÷ (128)1/7 + 482 = 4 × ? + 846
