Question
Bittu can finish a task by
himself in 60 days, while Anoop and Bittu working together can complete the same task in 28 days. If Anoop starts the task alone and works for 35 days before stopping, how many additional days would Bittu need to complete the remaining work on his own?Solution
ATQ,
Let the total task = L.C.M of 60 and 28 = 420 units Then, efficiency of âBittuâ alone = 420 Ă· 60 = 7 units/day Combined efficiency of âAnoopâ and âBittuâ = 420 Ă· 28 = 15 units/day So, efficiency of âAnoopâ alone = 15 â 7 = 8 units/day task done by âAnoopâ alone in 35 days = 8 Ă 35 = 280 units Remaining task = 420 â 280 = 140 units So, time taken by âBittuâ alone to complete the remaining task = 140 Ă· 7 = 20 days.Â
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