Question
A man alone can do a work in 25 days. A woman can complete
half of the same work in 20 days. In how many days can they complete 90% of the work together?Solution
ATQ,
Time taken by the woman to finish the entire work = 20 á 0.5 = 40 days
Let the total work be 200 units. {LCM of (25 and 40)}
So, efficiency of the man = 200 á 25 = 8 units/day
And efficiency of the woman = 200 á 40 = 5 units/day
So, required time = (200 à 0.9) á (8 + 5) = 13.85 days
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