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    • Question

      A man completes a work in 16 days. A woman finishes half of

      that work in 10 days. How many days will they take together to finish 75% of the work?
      A 15.5 days Correct Answer Incorrect Answer
      B 17.2 days Correct Answer Incorrect Answer
      C 6.67 days Correct Answer Incorrect Answer
      D 9.6 days Correct Answer Incorrect Answer

      Solution

      ATQ,

      Time taken by the woman to finish the entire work = 10 ÷ 0.5 = 20 days

      Let the total work be 80 units. {LCM of (16 and 20)}

      So, efficiency of the man = 80 ÷ 16 = 5 units/day

      And efficiency of the woman = 80 ÷ 20 = 4 units/day

      So, required time = (80 × 0.75) ÷ (5 + 4) = 6.67 days

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