Question
‘A’ can finish a project in 40 days, whereas ‘B’ finishes 50% of the project in 12 days less than ‘A’. How many days will it take both ‘A’ and ‘B’ to complete 90% of the project together?
Solution
Time taken by ‘B’ to complete the whole work = (40 – 12)/0.5 = 56 days Let the total work = 280 units Efficiency of ‘A’ = 280/40 = 7 units/day Efficiency of ‘B’ = 280/56 = 5 units/day Required time taken = {(0.9 × 280)/(7 + 5)} = 252/12 = 21 days
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