Question
βAβ can finish a project in 40 days, whereas βBβ
finishes 50% of the project in 12 days less than βAβ. How many days will it take both βAβ and βBβ to complete 90% of the project together?Solution
Time taken by βBβ to complete the whole work = (40 β 12)/0.5 = 56 days Let the total work = 280 units Efficiency of βAβ = 280/40 = 7 units/day Efficiency of βBβ = 280/56 = 5 units/day Required time taken = {(0.9 Γ 280)/(7 + 5)} = 252/12 =Β 21 days
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