Question

A tank is filled by three pipes with uniform flow. The first two pipes operating simultaneously fill the tank in the same time during which the tank is filled by the third pipe alone. The second pipe fills the tank 45 hours faster than the first pipe and 4 hours slower than the third pipe. The time required by the first pipe is?

Q: Answer-&lt;p&gt;A tank is filled by three pipes with uniform flow. The first two pipes operating simultaneo...

Let time taken by third pipe to fill the tank x hrs so time taken by 2nd pipe to fill the tank x 4 hrs amp time taken by 1st pipe to fill the tank x 4 45 x 49 hrs Hence 1x4 1x49 1x x 4 x 49 x 4x 49 1x 2x 53x2 53x 196 1x 2x2 53x x2 53x 196 x2 196 x 14 hrs So time taken by 1st pipe to fill the tank x 49 14 49 63 hrs Alternate Method - Let time taken by third pipe to fill the tank x hrs so time taken by 2nd pipe to fill the tank x 4 hrs amp time taken by 1st pipe to fill the tank x 4 45 x 49 hrs Then x root of 4 times 49 root of 196 14 hrs So time taken by 1st pipe to fill the tank x 49 14 49 63 hrs.