Question
A contractor planned to complete a project in 5 days by employing ‘a’ workers. But every day exactly 15 workers were absent. As a result, the work got completed in 3/5 more time than usual. Find the value of ‘a’.
Solution
ATQ, Usual time = 5 days 3/5 more time than usual ⇒ Actual time = 5 × (1 + 3/5) = 5 × 8/5 = 8 days Total work = a × 5 = (a − 15) × 8 So, 5a = 8a − 120 3a = 120 a = 40 Therefore, the contractor originally employed 40 workers.
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