Question
A can finish a piece of work in 15 days and B can finish
it in 20 days. They work together for 4 days and then B leaves. In how many more days can A alone finish the remaining work?Solution
ATQ, Assume total work = LCM(15, 20) = 60 units. A’s rate = 60/15 = 4 units/day B’s rate = 60/20 = 3 units/day Together in 1 day = 4 + 3 = 7 units In 4 days they complete = 7 × 4 = 28 units Remaining work = 60 − 28 = 32 units A alone does 4 units/day Required days = 32 / 4 = 8 days
12, 24, 72, 288, 1440, ?
2 5 16 65 326 ?
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...133    183    220    ?     263     273
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