Question
A alone can complete 40% of a work in 18 days while B
takes 15 days more than A to complete it. If B and C together can complete the work in 20 days, then find the time taken by C alone to complete the same work.Solution
Time taken by A alone to complete the entire work = 18/0.4 = 45 days Time taken by B alone to complete the entire work = 45 + 15 = 60 days Let the total work = L.C.M of 45, 60 and 20 = 180 units Then, efficiency of B = (180/60) = 3 units/day Combined efficiency of B and C = (180/20) = 9 units/day So, efficiency of C alone = 9 – 3 = 6 units/day So, time taken by C alone to complete the entire work = (180/6) = 30 days
Client has breached debt covenants; lender issued waiver valid for 9 months after balance sheet date. Auditor notes liquidity support from group company...
During a statutory audit, the auditor discovers a pattern of journal entries posted near year-end reversing shortly after year-end that inflate reported...
Which auditing standard outlines the auditor's responsibilities relating to fraud in an audit of financial statements?
Which of the following financial statements can be prepared using a receipt and payment account?
Who is primarily responsible for preventing and detecting frauds in an organisation?
Suppose an NPO receives a donation of $10,000 from a donor. The entry to record this transaction would be as follows?
An auditor finds material misstatements due to fraud but the management refuses to take corrective action. What should be the auditor’s next step?
The scope of internal audit is decided by the :
As per SA 230, audit working papers must be retained for:
Which of the following constitutes the most reliable audit evidence?
Relevant for Exams:
