Question
A alone can complete 50% of a work in 9 days while B
takes 6 days more than A to complete it. If B and C together can complete the work in 12 days, then find the time taken by C alone to complete the same work.Solution
Time taken by A alone to complete the entire work = 9/0.5 = 18 days Time taken by B alone to complete the entire work = 18 + 6 = 24 days Let the total work = L.C.M of 18, 24 and 12 = 72 units Then, efficiency of B = (72/24) = 3 units/day Combined efficiency of B and C = (72/12) = 6 units/day So, efficiency of C alone = 6 – 3 = 3 units/day So, time taken by C alone to complete the entire work = (72/3) = 24 days
Determine the value of k such that the points A(2,3), B(4,k), and C(6,-3) lie on the same straight line.
Solve the given equation for ?. Find the approximate value.
(3/5 of 399.78 + 7/9 of 360.15) ÷ (√63.94 + 25% of 383.94) = ?
...[{(√785) % of 449.85}/(35.89 × 7.14 + 849.89 ÷ 5.12 + 199.78% of 41.09)] = ( 1/? )Â
65.22 of 359.98% + 459.99 ÷ 23.18 = ?
{(23.65 × 35.12) ÷ 6.97} + 179.86 = ? × 14.76
What approximate value will come in place of the question mark (?) in the following question? (Note: You are not expected to calculate the exact value.)...
- What approximate value will come in place of the question mark (?) in the following question? (Note: You are not expected to calculate the exact value.)
- What approximate value will come in place of the question mark (?) in the following question? (Note: You are not expected to calculate the exact value.)
What will come in place of the question mark (?) in the following series?
50, 25, 25, ?, 75, 187.5
What approximate value will replace the question mark (?) in the following?
? + 1...