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    Question

    A alone can complete 50% of a work in 20 days while B

    takes 16 days more than A to complete it. If B and C together can complete the work in 24 days, then find the time taken by C alone to complete the same work.
    A 30 days Correct Answer Incorrect Answer
    B 40 days Correct Answer Incorrect Answer
    C 24 days Correct Answer Incorrect Answer
    D 42 days Correct Answer Incorrect Answer
    E 21 days Correct Answer Incorrect Answer

    Solution

    Time taken by A alone to complete the entire work = 20/0.5 = 40 days Time taken by B alone to complete the entire work = 40 + 16 = 56 days Let the total work = L.C.M of 56, 40 and 24 = 840 units Then, efficiency of B = (840/56) = 15 units/day Combined efficiency of B and C = (840/24) = 35 units/day So, efficiency of C alone = 35 ā€“ 15 = 20 units/day So, time taken by C alone to complete the entire work = (840/20) = 42 days

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