Question
A alone can complete 50% of a work in 20 days while B
takes 16 days more than A to complete it. If B and C together can complete the work in 24 days, then find the time taken by C alone to complete the same work.Solution
Time taken by A alone to complete the entire work = 20/0.5 = 40 days Time taken by B alone to complete the entire work = 40 + 16 = 56 days Let the total work = L.C.M of 56, 40 and 24 = 840 units Then, efficiency of B = (840/56) = 15 units/day Combined efficiency of B and C = (840/24) = 35 units/day So, efficiency of C alone = 35 – 15 = 20 units/day So, time taken by C alone to complete the entire work = (840/20) = 42 days
According to Herzberg's motivation hygiene theory which of the following has been matched correctly:
A.        Motivation factor - A...
When should a risk be avoided?
How much interest subvention is provided under PM SVaNIDHI Scheme to the borrowers
Which of the following is not considered a major financial center in the Asia-Pacific region?
To ensure that employees are satisfied with their performance appraisals, supervisors should ascertain that employees ____________
When shares are forfeited due to non-payment of call money, the amounts previously paid by the shareholder are credited to the Share Forfeiture Account....
Pey Jal Survekshan will serve as a monitoring tool and an accelerator for the AMRUT Mission while also fostering healthy competition among cities. Mini...
Risks that could arise due to legal actions or uncertainty of interpretations of contracts & agreements is called
XYZ Corporation is financed by 30% equity and 70% by debt. The company has an after-tax cost of debt of 9% and the beta of shares in XYZ is 2. The risk-...
Which section of the MSMED Act, 2006 provides for the registration of associations of MSMEs?