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Let the total work = 200 units Then, efficiency of ‘A’ = (200/50) = 4 units/hour Work completed by ‘A’ alone in 20 hours = 4 × 20 = 80 units Remaining work = 200 – 80 = 120 units So, efficiency of ‘B’ = 120/10 = 12 units/hour Therefore, combined efficiency of ‘A’ and ‘B’ = 12 + 4 = 16 units/hour So, time taken by ‘A’ and ‘B’ together to complete the work = (200/16) = 12.5 hours
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