Question
‘A’ alone can complete a work in 40 hours. ‘A’
started the work alone and left after working on it for 20 hours. If ‘B’ completed the rest of the work in 20 hours then find the time taken by ‘A’ and ‘B’ together to complete the whole work.Solution
Let the total work = 300 units Then, efficiency of ‘A’ = (300/40) = 7.5 units/hour Work completed by ‘A’ alone in 20 hours = 7.5 × 20 = 150 units Remaining work = 300 – 150 = 150 units So, efficiency of ‘B’ = 150/20 = 7.5 units/hour Therefore, combined efficiency of ‘A’ and ‘B’ = 7.5 + 7.5 = 15 units/hour So, time taken by ‘A’ and ‘B’ together to complete the work = (300/15) = 20 hours
More Time and work Questions
64.5% of 800 + 36.4% of 1500 = (?)² + 38
√256 * 3 – 15% of 300 + ? = 150% of 160
82% of 400 + √(?) = 130% of 600 - 85% of 400
25% of 140 + 2 × 8 = ? + 9 × 5
- What will come in place of the question mark (?) in the following questions?
120÷(5×2)+8=? 4.7 × 3.5 + 4.2 × 4.5 = 22.5 × 3.5 - ?
180 ÷ 3 of 2 = 102 – ?
36 × 15 + 20% 1250 = ? + 296
(1296) -3/4 = ?
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