Question
Perimeter of square is 48 cm and length of a rectangle
is equal to side of square and breadth of rectangle is 4 cm less than length of the rectangle. Find the area of rectangle.Solution
Let the length and breadth of rectangle be ‘l’ cm & ‘b’ cm respectively. Let the side of a square be ‘a’ cm. Perimeter of square = 48 cm => 4a = 48 cm => a = 12 cm So, l = 12 cm According to question, b =12 − 4 = 8 cm Required area = 12 × 8 = 96 cm2
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