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      Question

      'A' alone can do some work in 20 days. 'B' is 60% more

      efficient than 'A'. 'A' worked alone for 12 days and left. How much time (in days) does 'B' need to finish the remaining work?
      A 5 days Correct Answer Incorrect Answer
      B 6 days Correct Answer Incorrect Answer
      C 4 days Correct Answer Incorrect Answer
      D 9 days Correct Answer Incorrect Answer

      Solution

      Let the efficiency of 'A' be x units/day.
      So, efficiency of 'B' = 1.6x units/day.
      Total work = 20 × x = 20x units.
      Work done by 'A' in twelve days = 12 × x = 12x units.
      Remaining work = 20x − 12x = 8x units.
      Time taken by 'B' to finish the remaining work = ({8x/1.6x} = 5) days.

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