Question
Arjun and Bheem can do a piece of work in 8 and 10 days
respectively. If they started the work together and worked on it for 3 days, then find the time taken by B alone to complete the remaining work.Solution
ATQ, Let we can assume that the total work be 40 units Arjun ’s one-day work will be then= 5 units Bheem’s one-day work = 4 units Then, Work done by Arjun and Bheem together in 3 days = 9 x 3 = 27 days Therefore, the rest work will be = 40 – 27 = 13 units Hence, the required number of days will be = 13/4 = 3.25 days
?% of 1499.89 + 54.14 × 8 = 25.05% of 5568.08
? = 41.92% of (34.92 x 40.42) + 29.78% of 399.84
- What approximate value will come in place of the question mark (?) in the following question? (Note: You are not expected to calculate the exact value.)
(15.87% of 79.98 + 19.69% of 64.22) × 4.83 = ?
? + 163.99 – 108.01 = 25.01 × 6.98
80.09 * √144.05+ ? * √224.87 = (2109.09 ÷ √1368.79) * 19.89
(15.15 ×  31.98) + 30.15% of 719.99 = ? + 124.34
(124.99)² = ?
6.992 + (2.01 × 2.98) + ? = 175.03
(627.98 ÷ 3.98 + 11.01 X 12.98 - ?) ÷ √623 = (178.98 + 37.08) ÷ 23.98Â
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