Question
Arjun and Bheem can do a piece of work in 8 and 10 days
respectively. If they started the work together and worked on it for 3 days, then find the time taken by B alone to complete the remaining work.Solution
ATQ, Let we can assume that the total work be 40 units Arjun ’s one-day work will be then= 5 units Bheem’s one-day work = 4 units Then, Work done by Arjun and Bheem together in 3 days = 9 x 3 = 27 days Therefore, the rest work will be = 40 – 27 = 13 units Hence, the required number of days will be = 13/4 = 3.25 days
I. x2 – 3(x + 5) = -11
II. y2 – 4(y + 2) = -2y
I. 96y² - 76y – 77 = 0
II. 6x² - 19x + 15 = 0
I. x2 + 91 = 20x
II. 10y2 - 29y + 21 = 0
I. 4x² - 21 x + 20 = 0
II. 8y² - 22 y + 15 = 0
Solve the quadratic equations and determine the relation between x and y:
Equation 1: x² - 36x + 288 = 0
Equation 2: y² - 36y + 320 = 0
I. Â 2(x+2)+ 2(-x)=5
II. Â (1/(y+1)+ 1/(y+5))=(1/(y+2)+ Â 1/(y+4))
Solve the quadratic equations and determine the relation between x and y:
Equation 1: 3x² + 6x - 9 = 0
Equation 2: 2y² - 16y + 32 = 0
Solve the quadratic equations and determine the relation between x and y:
Equation 1: x² - 45x + 450 = 0
Equation 2: y² - 48y + 540 = 0�...
 If x satisfies x² – 14x + 40 = 0, find x.
I. 3x2 – 16x + 21 = 0
II. y2 – 13y + 42 = 0
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