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    Question

    ‘R’ and ‘S’ can complete an assignment in 72

    days and 90 days respectively while ‘R’, ‘S’ and ‘T’ together can complete the same assignment in 24 days. Find the time taken by ‘T’ alone to complete 30% of the work.
    A 12 days Correct Answer Incorrect Answer
    B 18 days Correct Answer Incorrect Answer
    C 10 days Correct Answer Incorrect Answer
    D 22 days Correct Answer Incorrect Answer
    E None of these Correct Answer Incorrect Answer

    Solution

    ATQ Let total amount of work = 360 units (LCM of 72 and 90) Amount of work done by ‘R’ in one day = 360/72 = 5 units Amount of work done by ‘S’ in one day = 360/90 = 4 units Amount of work done by ‘R’, ‘S’ and ‘T’ in one day = 360/24 = 15 units Amount of work done by ‘T’ in one day = 15 – 5 – 4 = 6 units Desired time = (0.30 × 360)/6 = 18 days

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