Question
βRβ and βSβ can complete an assignment in 72
days and 90 days respectively while βRβ, βSβ and βTβ together can complete the same assignment in 24 days. Find the time taken by βTβ alone to complete 30% of the work.Solution
ATQ Let total amount of work = 360 units (LCM of 72 and 90) Amount of work done by βRβ in one day = 360/72 = 5 units Amount of work done by βSβ in one day = 360/90 = 4 units Amount of work done by βRβ, βSβ and βTβ in one day = 360/24 = 15 units Amount of work done by βTβ in one day = 15 β 5 β 4 = 6 units Desired time = (0.30 Γ 360)/6 = 18 days
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