Question
I. 2x² - 9x + 10 = 0 II. 3y² + 11y + 6
= 0 In the following questions, two equations numbered I and II are given. You have to solve both the equations and give answer.Solution
I. 2x² - 9x + 10 = 0 2x² - 5x - 4 x + 10 = 0 x (2 x – 5) – 2(2 x – 5) = 0 (x – 2) (2 x – 5) = 0 x = 2, 5/2 II. 3y² + 11y + 6 = 0 3y² + 2y + 9 y + 6 = 0 y (3 y + 2) + 3(3 y + 2) = 0 y = -3, -2/3 Hence, x>y
I. x2 – 36 = 0
II. y2 - 7y + 6 = 0
In the question, two equations I and II are given. You have to solve both the equations to establish the correct relation between x and y.
I. 2x<...
I. x2 – 10x + 21 = 0
II. y2 + 11y + 28 = 0
Solve the quadratic equations and determine the relation between x and y:
Equation 1: x² - 5x + 6 = 0
Equation 2: y² - 7y + 12 = 0
I.√(3x-17)+ x=15
II. Â y+ Â 135/y=24Â
Find the roots of the equation 6p² – 5p – 6 = 0.
If α, β are the roots of the equation x² – px + q = 0, then the value of α2+β2+2αβ isÂ
...I. 63x² + 146x + 80 = 0
II. 42y² + 109y + 70 = 0
I. 3x2 – 16x + 21 = 0
II. y2 – 13y + 42 = 0
I. √(74x-250 )– x=15
II. √(3y²-37y+18)+ 2y=18
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